Автор: Anton

Wed, 12 Apr 2017 09:25:32 +0000

Автор: vombat

Tue, 11 Apr 2017 17:24:28 +0000

#include<stdio.h>

int main(void){
	int a, b, c;

	printf("a:");
	scanf("%i", &a);
	printf("b:");
	scanf("%i", &b);
	printf("c:");
	scanf("%i", &c);

	if(a > 0) a = 1; else a = 0;
	if(b > 0) b = 1; else b = 0;
	if(c > 0) c = 1; else c = 0;

	printf("positive numbers:%i\nnegative numbers:%i\n",
		(a + b + c), 3 - (a + b + c));

	return 0;
}

#include

int main(void){

int a, b, c;

printf("a:");

scanf("%i", &a);

printf("b:");

scanf("%i", &b);

printf("c:");

scanf("%i", &c);

if(a > 0) a = 1; else a = 0;

if(b > 0) b = 1; else b = 0;

if(c > 0) c = 1; else c = 0;

printf("positive numbers:%i\nnegative numbers:%i\n",

(a + b + c), 3 - (a + b + c));

return 0;

}

]]>

Комментарии: Решаем задачи Абрамян на C. If5

Автор: Anton

Автор: vombat